Math Component

A cannonball is shot upward from the upper deck of a fort with an initial velocity of 192 feet per second.  The deck is 32 feet above the ground. 

Quadratic Model: h = -16t²+192t+32

How high does the cannonball go?  608 feet
How long is the cannonball in the air? 12.16 seconds

Steps for Solving:

1. Plug 192 feet per second in for v₀ and 32 feet for h₀
2. Plug formula into calculator and graph
3. Go to the table and find the vertex of the graph (this is how high the cannonball went)
4. Using the quadratic formula, find the positive x-intercept (this is how long the cannonball was in the air)
5. Check your work